急高数题 帮忙解 计算I=∫∫(3-x-y)dxdy,其中D: 0<=x<=1,0<=y<=2...
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发布时间：2024-10-23 07:35
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时间：2024-11-21 15:41
∫∫(3-x-y)dxdy
=∫[0-->1]∫[0-->2] (3-x-y) dydx
=∫[0-->1] (3y-xy-1/2y²) |[0-->2]dx
=∫[0-->1] (6-2x-2) dx
=∫[0-->1] (4-2x) dx
=(4x-x²) [0-->1]
=3
